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		<id>http://wiki.sommarmatte.se/wikis/2009/bridgecourse2-TU-Berlin/index.php?action=history&amp;feed=atom&amp;title=Antwort_1.2%3A3</id>
		<title>Antwort 1.2:3 - Versionsgeschichte</title>
		<link rel="self" type="application/atom+xml" href="http://wiki.sommarmatte.se/wikis/2009/bridgecourse2-TU-Berlin/index.php?action=history&amp;feed=atom&amp;title=Antwort_1.2%3A3"/>
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		<updated>2026-05-03T13:33:48Z</updated>
		<subtitle>Versionsgeschichte für diese Seite in Online Mathematik Brückenkurs 2</subtitle>
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	<entry>
		<id>http://wiki.sommarmatte.se/wikis/2009/bridgecourse2-TU-Berlin/index.php?title=Antwort_1.2:3&amp;diff=3412&amp;oldid=prev</id>
		<title>Tekbot: Answer 1.2:3 moved to Antwort 1.2:3: Robot: moved page</title>
		<link rel="alternate" type="text/html" href="http://wiki.sommarmatte.se/wikis/2009/bridgecourse2-TU-Berlin/index.php?title=Antwort_1.2:3&amp;diff=3412&amp;oldid=prev"/>
				<updated>2009-03-11T09:02:51Z</updated>
		
		<summary type="html">&lt;p&gt;&lt;a href=&quot;/wikis/2009/bridgecourse2-TU-Berlin/index.php?title=Answer_1.2:3&amp;amp;action=edit&quot; class=&quot;new&quot; title=&quot;Answer 1.2:3&quot;&gt;Answer 1.2:3&lt;/a&gt; moved to &lt;a href=&quot;/wikis/2009/bridgecourse2-TU-Berlin/index.php/Antwort_1.2:3&quot; title=&quot;Antwort 1.2:3&quot;&gt;Antwort 1.2:3&lt;/a&gt;: Robot: moved page&lt;/p&gt;

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				&lt;td colspan='2' style=&quot;background-color: white; color:black;&quot;&gt;← Nächstältere Version&lt;/td&gt;
				&lt;td colspan='2' style=&quot;background-color: white; color:black;&quot;&gt;Version vom 09:02, 11. Mär. 2009&lt;/td&gt;
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		&lt;/table&gt;</summary>
		<author><name>Tekbot</name></author>	</entry>

	<entry>
		<id>http://wiki.sommarmatte.se/wikis/2009/bridgecourse2-TU-Berlin/index.php?title=Antwort_1.2:3&amp;diff=1477&amp;oldid=prev</id>
		<title>Tekbot: Svar 1.2:3 moved to Answer 1.2:3: Robot: moved page</title>
		<link rel="alternate" type="text/html" href="http://wiki.sommarmatte.se/wikis/2009/bridgecourse2-TU-Berlin/index.php?title=Antwort_1.2:3&amp;diff=1477&amp;oldid=prev"/>
				<updated>2008-09-16T13:57:37Z</updated>
		
		<summary type="html">&lt;p&gt;&lt;a href=&quot;/wikis/2009/bridgecourse2-TU-Berlin/index.php?title=Svar_1.2:3&amp;amp;action=edit&quot; class=&quot;new&quot; title=&quot;Svar 1.2:3&quot;&gt;Svar 1.2:3&lt;/a&gt; moved to &lt;a href=&quot;/wikis/2009/bridgecourse2-TU-Berlin/index.php?title=Answer_1.2:3&amp;amp;action=edit&quot; class=&quot;new&quot; title=&quot;Answer 1.2:3&quot;&gt;Answer 1.2:3&lt;/a&gt;: Robot: moved page&lt;/p&gt;

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				&lt;td colspan='2' style=&quot;background-color: white; color:black;&quot;&gt;← Nächstältere Version&lt;/td&gt;
				&lt;td colspan='2' style=&quot;background-color: white; color:black;&quot;&gt;Version vom 13:57, 16. Sep. 2008&lt;/td&gt;
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		<author><name>Tekbot</name></author>	</entry>

	<entry>
		<id>http://wiki.sommarmatte.se/wikis/2009/bridgecourse2-TU-Berlin/index.php?title=Antwort_1.2:3&amp;diff=133&amp;oldid=prev</id>
		<title>Oskar: Ny sida: {| width=&quot;100%&quot; cellspacing=&quot;10px&quot; |a) |width=&quot;33%&quot;| &lt;math&gt;\displaystyle\frac{1}{2\sqrt{x}\sqrt{x+1}}&lt;/math&gt; |b) |width=&quot;33%&quot;| &lt;math&gt;\displaystyle - \frac{1}{(x-1)^{3/2}\sqrt{x+1}}&lt;/math&gt; |...</title>
		<link rel="alternate" type="text/html" href="http://wiki.sommarmatte.se/wikis/2009/bridgecourse2-TU-Berlin/index.php?title=Antwort_1.2:3&amp;diff=133&amp;oldid=prev"/>
				<updated>2008-04-04T08:14:42Z</updated>
		
		<summary type="html">&lt;p&gt;Ny sida: {| width=&amp;quot;100%&amp;quot; cellspacing=&amp;quot;10px&amp;quot; |a) |width=&amp;quot;33%&amp;quot;| &amp;lt;math&amp;gt;\displaystyle\frac{1}{2\sqrt{x}\sqrt{x+1}}&amp;lt;/math&amp;gt; |b) |width=&amp;quot;33%&amp;quot;| &amp;lt;math&amp;gt;\displaystyle - \frac{1}{(x-1)^{3/2}\sqrt{x+1}}&amp;lt;/math&amp;gt; |...&lt;/p&gt;
&lt;p&gt;&lt;b&gt;Neue Seite&lt;/b&gt;&lt;/p&gt;&lt;div&gt;{| width=&amp;quot;100%&amp;quot; cellspacing=&amp;quot;10px&amp;quot;&lt;br /&gt;
|a)&lt;br /&gt;
|width=&amp;quot;33%&amp;quot;| &amp;lt;math&amp;gt;\displaystyle\frac{1}{2\sqrt{x}\sqrt{x+1}}&amp;lt;/math&amp;gt;&lt;br /&gt;
|b)&lt;br /&gt;
|width=&amp;quot;33%&amp;quot;| &amp;lt;math&amp;gt;\displaystyle - \frac{1}{(x-1)^{3/2}\sqrt{x+1}}&amp;lt;/math&amp;gt;&lt;br /&gt;
|c)&lt;br /&gt;
|width=&amp;quot;33%&amp;quot;| &amp;lt;math&amp;gt;\displaystyle - \frac{1-2x^2}{x^2(1-x^2)^{3/2}}&amp;lt;/math&amp;gt;&lt;br /&gt;
|-&lt;br /&gt;
|d)&lt;br /&gt;
|width=&amp;quot;33%&amp;quot;| &amp;lt;math&amp;gt;-\cos\cos\sin x \cdot \sin\sin x \cdot \cos x&amp;lt;/math&amp;gt;&lt;br /&gt;
|e)&lt;br /&gt;
|width=&amp;quot;33%&amp;quot;| &amp;lt;math&amp;gt;e^{\sin x^2}\cdot \cos x^2 \cdot 2x&amp;lt;/math&amp;gt;&lt;br /&gt;
|f)&lt;br /&gt;
|width=&amp;quot;33%&amp;quot;| &amp;lt;math&amp;gt;\displaystyle x^{\tan x}\Bigl(\frac{\ln x}{\cos^2x}+\frac{\tan x}{x}\Bigr)&amp;lt;/math&amp;gt;&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Oskar</name></author>	</entry>

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