Answer 2.2:3
From Förberedande kurs i matematik 2
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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|<math>-\cos x^2+C</math> |b) |width="50%"| <math>\displaystyle\frac{\sin^2x}{2}+C</math> |- |c) |width="50%"| <math>\frac{1}{2}(\ln x)^2+...)
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Revision as of 09:06, 7 April 2008
| a) | \displaystyle -\cos x^2+C | b) | \displaystyle \displaystyle\frac{\sin^2x}{2}+C |
| c) | \displaystyle \frac{1}{2}(\ln x)^2+C | d) | \displaystyle \displaystyle\frac{1}{2}\ln\left(x^2+2x+2\right)+C |
| e) | \displaystyle \displaystyle\frac{3}{2}\ln\left(x^2+1\right)+C | f) | \displaystyle -2\cos\sqrt{x}+C |
