3.3 Exercises

From Förberedande kurs i matematik 2

(Difference between revisions)
Jump to: navigation, search
Current revision (11:24, 31 July 2009) (edit) (undo)
(Changed exercise 3.3:4c)
 
(11 intermediate revisions not shown.)
Line 2: Line 2:
{| border="0" cellspacing="0" cellpadding="0" height="30" width="100%"
{| border="0" cellspacing="0" cellpadding="0" height="30" width="100%"
| style="border-bottom:1px solid #000" width="5px" |  
| style="border-bottom:1px solid #000" width="5px" |  
-
{{Mall:Ej vald flik|[[3.3 Potenser och rötter|Teori]]}}
+
{{Not selected tab|[[3.3 Powers and roots|Theory]]}}
-
{{Mall:Vald flik|[[3.3 Övningar|Övningar]]}}
+
{{Selected tab|[[3.3 Exercises|Exercises]]}}
| style="border-bottom:1px solid #000" width="100%"|  
| style="border-bottom:1px solid #000" width="100%"|  
|}
|}
-
===Övning 3.3:1===
+
===Exercise 3.3:1===
<div class="ovning">
<div class="ovning">
-
Skriv följande tal i formen <math>\,a+ib\,</math>, där <math>\,a\,</math> och <math>\,b\,</math> är reella tal.
+
Write the following number in the form <math>\,a+ib\,</math>, where <math>\,a\,</math> and <math>\,b\,</math> are real numbers:
{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
Line 24: Line 24:
|width="50%"| <math>\displaystyle\frac{(1+i\sqrt{3}\,)(1-i)^8}{(\sqrt{3}-i)^9}</math>
|width="50%"| <math>\displaystyle\frac{(1+i\sqrt{3}\,)(1-i)^8}{(\sqrt{3}-i)^9}</math>
|}
|}
-
</div>{{#NAVCONTENT:Svar|Svar 3.3:1|Lösning a|Lösning 3.3:1a|Lösning b|Lösning 3.3:1b|Lösning c|Lösning 3.3:1c|Lösning d|Lösning 3.3:1d|Lösning e|Lösning 3.3:1e}}
+
</div>{{#NAVCONTENT:Answer|Answer 3.3:1|Solution a|Solution 3.3:1a|Solution b|Solution 3.3:1b|Solution c|Solution 3.3:1c|Solution d|Solution 3.3:1d|Solution e|Solution 3.3:1e}}
-
===Övning 3.3:2===
+
===Exercise 3.3:2===
<div class="ovning">
<div class="ovning">
-
Lös ekvationerna
+
Solve the equations
{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
Line 42: Line 42:
|width="33%"| <math>\displaystyle\Bigl(\frac{z+i}{z-i}\Bigr)^2 = -1</math>
|width="33%"| <math>\displaystyle\Bigl(\frac{z+i}{z-i}\Bigr)^2 = -1</math>
|}
|}
-
</div>{{#NAVCONTENT:Svar|Svar 3.3:2|Lösning a|Lösning 3.3:2a|Lösning b|Lösning 3.3:2b|Lösning c|Lösning 3.3:2c|Lösning d|Lösning 3.3:2d|Lösning e|Lösning 3.3:2e}}
+
</div>{{#NAVCONTENT:Answer|Answer 3.3:2|Solution a|Solution 3.3:2a|Solution b|Solution 3.3:2b|Solution c|Solution 3.3:2c|Solution d|Solution 3.3:2d|Solution e|Solution 3.3:2e}}
-
===Övning 3.3:3===
+
===Exercise 3.3:3===
<div class="ovning">
<div class="ovning">
-
Kvadratkomplettera följande uttryck
+
Complete the square of the following expressions
{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
Line 58: Line 58:
|width="50%"| <math>iz^2+(2+3i)z-1</math>
|width="50%"| <math>iz^2+(2+3i)z-1</math>
|}
|}
-
</div>{{#NAVCONTENT:Svar|Svar 3.3:3|Lösning a|Lösning 3.3:3a|Lösning b|Lösning 3.3:3b|Lösning c|Lösning 3.3:3c|Lösning d|Lösning 3.3:3d}}
+
</div>{{#NAVCONTENT:Answer|Answer 3.3:3|Solution a|Solution 3.3:3a|Solution b|Solution 3.3:3b|Solution c|Solution 3.3:3c|Solution d|Solution 3.3:3d}}
-
===Övning 3.3:4===
+
===Exercise 3.3:4===
<div class="ovning">
<div class="ovning">
-
Lös ekvationerna
+
Solve the equations
{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
Line 70: Line 70:
|-
|-
|c)
|c)
-
|width="50%"| <math>-z^2+2z+3=0</math>
+
|width="50%"| <math>z^2+2z+3=0</math>
|d)
|d)
|width="50%"| <math>\displaystyle\frac{1}{z} + z = \frac{1}{2}</math>
|width="50%"| <math>\displaystyle\frac{1}{z} + z = \frac{1}{2}</math>
|}
|}
-
</div>{{#NAVCONTENT:Svar|Svar 3.3:4|Lösning a|Lösning 3.3:4a|Lösning b|Lösning 3.3:4b|Lösning c|Lösning 3.3:4c|Lösning d|Lösning 3.3:4d}}
+
</div>{{#NAVCONTENT:Answer|Answer 3.3:4|Solution a|Solution 3.3:4a|Solution b|Solution 3.3:4b|Solution c|Solution 3.3:4c|Solution d|Solution 3.3:4d}}
-
===Övning 3.3:5===
+
===Exercise 3.3:5===
<div class="ovning">
<div class="ovning">
-
Lös ekvationerna
+
Solve the equations
{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
Line 90: Line 90:
|width="50%"| <math>(4+i)z^2+(1-21i)z=17</math>
|width="50%"| <math>(4+i)z^2+(1-21i)z=17</math>
|}
|}
-
</div>{{#NAVCONTENT:Svar|Svar 3.3:5|Lösning a|Lösning 3.3:5a|Lösning b|Lösning 3.3:5b|Lösning c|Lösning 3.3:5c|Lösning d|Lösning 3.3:5d}}
+
</div>{{#NAVCONTENT:Answer|Answer 3.3:5|Solution a|Solution 3.3:5a|Solution b|Solution 3.3:5b|Solution c|Solution 3.3:5c|Solution d|Solution 3.3:5d}}
 +
 
 +
===Exercise 3.3:6===
 +
<div class="ovning">
 +
Determine the solution to <math>\,z^2=1+i\,</math> both in polar form and in the form <math>\,a+ib\,</math>, where <math>\,a\,</math> and <math>\,b\,</math> are real numbers. Use the result to calculate <math>\; \tan \frac{\pi}{8}\,</math>.
 +
</div>{{#NAVCONTENT:Answer|Answer 3.3:6|Solution|Solution 3.3:6}}

Current revision

       Theory          Exercises      

Exercise 3.3:1

Write the following number in the form \displaystyle \,a+ib\,, where \displaystyle \,a\, and \displaystyle \,b\, are real numbers:

a) \displaystyle (i+1)^{12} b) \displaystyle \displaystyle\Bigl(\frac{1+i\sqrt{3}}{2}\,\Bigr)^{12}
c) \displaystyle (4\sqrt{3} -4i)^{22} d) \displaystyle \Bigl(\displaystyle\frac{1+i\sqrt{3}}{1+i}\,\Bigr)^{12}
e) \displaystyle \displaystyle\frac{(1+i\sqrt{3}\,)(1-i)^8}{(\sqrt{3}-i)^9}

Exercise 3.3:2

Solve the equations

a) \displaystyle z^4=1 b) \displaystyle z^3=-1 c) \displaystyle z^5=-1-i
d) \displaystyle (z-1)^4+4=0 e) \displaystyle \displaystyle\Bigl(\frac{z+i}{z-i}\Bigr)^2 = -1

Exercise 3.3:3

Complete the square of the following expressions

a) \displaystyle z^2 +2z+3 b) \displaystyle z^2 +3iz-\frac{1}{4}
c) \displaystyle -z^2-2iz +4z+1 d) \displaystyle iz^2+(2+3i)z-1

Exercise 3.3:4

Solve the equations

a) \displaystyle z^2=i b) \displaystyle z^2-4z+5=0
c) \displaystyle z^2+2z+3=0 d) \displaystyle \displaystyle\frac{1}{z} + z = \frac{1}{2}

Exercise 3.3:5

Solve the equations

a) \displaystyle z^2-2(1+i)z+2i-1=0 b) \displaystyle z^2-(2-i)z+(3-i)=0
c) \displaystyle z^2-(1+3i)z-4+3i=0 d) \displaystyle (4+i)z^2+(1-21i)z=17

Exercise 3.3:6

Determine the solution to \displaystyle \,z^2=1+i\, both in polar form and in the form \displaystyle \,a+ib\,, where \displaystyle \,a\, and \displaystyle \,b\, are real numbers. Use the result to calculate \displaystyle \; \tan \frac{\pi}{8}\,.