Antwort 4.3:4
Aus Online Mathematik Brückenkurs 1
| a) | \displaystyle 1-b^2 | b) | \displaystyle \sqrt{1-b^2} |
| c) | \displaystyle 2b\sqrt{1-b^2} | d) | \displaystyle 2b^2-1 |
| e) | \displaystyle \sqrt{1-b^2}\cdot\displaystyle \frac{1}{\sqrt{2}} + b\cdot \displaystyle \frac{1}{\sqrt{2}} | f) | \displaystyle b\cdot\displaystyle \frac{1}{2}+\sqrt{1-b^2}\cdot\displaystyle \frac{\sqrt{3}}{2} |
