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Lösung 4.3:4c

Version vom 15:05, 22. Okt. 2008 von Tekbot (Diskussion | Beiträge)

The formula for double angles gives

\displaystyle \sin 2v=2\sin v\cos v

and from exercise b, we have \displaystyle \sin v = \sqrt{1-b^2}\,. Thus,

\displaystyle \sin 2v = 2b\sqrt{1-b^2}\,\textrm{.}