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Lösung 3.3:3c

Version vom 14:34, 22. Okt. 2008 von Tekbot (Diskussion | Beiträge)

First, we rewrite the number 0.125 as a fraction which we also simplify

0.125=1251000=1035

25=(2

5)35

5=123=2−3.

Because 0.125 was expressed as a power of 2, the logarithm can be calculated in full

log20.125=log22−3=(−3)

log22=(−3)

1=−3.