Aus Online Mathematik Brückenkurs 1

In this right-angled triangle, the opposite and the hypotenuse are given. This means that we can directly set up a relation for the sine of the angle v,

\displaystyle \sin v = \frac{70}{110}\,\textrm{.}

The right-hand side in this equation can be simplified, so that we get

\displaystyle \sin v = \frac{7}{11}\,\textrm{.}