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Lösung 3.3:5f

Version vom 08:44, 22. Okt. 2008 von Tekbot (Diskussion | Beiträge)

Since \displaystyle \ln e=1, the whole expression becomes

\displaystyle \bigl(e^{\ln e}\bigr)^2 = \bigl(e^{1}\bigr)^2 = e^{1\cdot 2} = e^2\,\textrm{.}