Lösung 4.3:8a
Aus Online Mathematik Brückenkurs 1
We rewrite \displaystyle \tan v on the left-hand side as \displaystyle \frac{\sin v}{\cos v}, so that
If we then use the Pythagorean identity
and rewrite \displaystyle \cos^2\!v in the denominator as \displaystyle 1 - \sin^2\!v, we get what we are looking for on the right-hand side. The whole calculation is
