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Antwort 2.1:7

Version vom 12:07, 31. Mär. 2008 von Lina (Diskussion | Beiträge)

\displaystyle \displaystyle \frac{4}{(x+3)(x+5)}

\displaystyle \displaystyle \frac{x^4-x^3+x^2+x-1}{x^2(x-1)}

\displaystyle \displaystyle \frac{ax(a+1-x)}{(a+1)^2}