Lösung 3.3:3h
Aus Online Mathematik Brückenkurs 1
Because \displaystyle a^{2}\sqrt{a} = a^{2}a^{1/2} = a^{2+1/2} = a^{5/2}, the logarithm law, \displaystyle b\lg a = \lg a^b, gives that
where we have used that \displaystyle \log_{a}a = 1\,.
Note: In this exercise, we assume, implicitly, that \displaystyle a > 0 and \displaystyle a\ne 1\,.
