Lösung 3.3:3a

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By writing the argument \displaystyle 8 as \displaystyle 8 = 2\cdot 4 = 2\cdot 2\cdot 2 = 2^3, the logarithm law, \displaystyle \lg a^b = b\lg a, gives

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where we have used \displaystyle \log _{2}2 = 1\,.