Lösung 3.1:6c
Aus Online Mathematik Brückenkurs 1
The expression is so complicated that we first need to simplify it. We start with the three fractions, \displaystyle 1/\!\sqrt{3}, \displaystyle 1/\!\sqrt{5} and \displaystyle 1/\!\sqrt{2}, which contain root signs and multiply their numerators and denominators in such a way that the root signs end up only in the numerators
Then, multiply the top and bottom of the fraction by 2 so that we get rid of the fractions in the denominator
Now, we can multiply the top and bottom by the conjugate of the denominator \displaystyle \sqrt{2}+1, to get an expression without roots in the denominator.
