Lösung 3.1:3c

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We start by looking at one part of the expression \displaystyle \sqrt{16}. This subexpression can be simplified since \displaystyle 16 = 4\cdot 4 = 4^{2} which gives that \displaystyle \sqrt{16} = \sqrt{4^{2}} = 4 and the whole expression becomes

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Can \displaystyle \sqrt{20} be simplified? In order to answer this, we split 20 up into integer factors,

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and see that 20 contains the square \displaystyle 2^2 as a factor and can therefore be taken outside the root sign,

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