Processing Math: Done

Aus Online Mathematik Brückenkurs 1

This equation differs from earlier examples in that it contains two root terms, in which case it is not possible to get rid of all square roots at once with one squaring, but rather we need to work in two steps.

Squaring once gives

x+1+x+52=42 

and expanding the left-hand side with the squaring rule gives

x+12+2x+1x+5+x+52=16 

which, after simplification, results in the equation:

x+1+2x+1x+5+x+5=16 

Moving all the terms, other than the root term, over to the right-hand side,

2x+1x+5=−2x+10 

and squaring once again,

2x+1x+52=−2x+102 

at last gives an equation that is completely free of root signs:

4x+1x+5=−2x+102 

Expand both sides

4x2+6x+5=4x2−40x+100 

and then cancel the common x2-term,

24x+20=−40x+100

We can write this equation as 64x=80, which gives

x=6480=26245=522=45

Because we squared our original equation (twice), we have to verify the solution x=54 in order to be able to rule out that we have a false root:

LHS=

=45+1+45+5=49+425=23+25=28=4= 

=RHS

Thus, the equation has the solution x=54.