Lösung 2.1:4c
Aus Online Mathematik Brückenkurs 1
Instead of multiplying together the whole expression, and then reading off the coefficients, we investigate which terms from the three brackets together give terms in x¹ and x².
If we start with the term in x, we see that there is only one combination of a term from each bracket which, when multiplied, gives x¹,
so, the coefficient in front of x is \displaystyle 1\cdot 2 = 2\,.
As for x², we also have only one possible combination
The coefficient in front of x² is \displaystyle 3\cdot 2 = 6\,.
