Lösung 1.3:5f
Aus Online Mathematik Brückenkurs 1
The whole expression is quite complicated, so it can be useful to simplify the terms \displaystyle \bigl(125^{\frac{1}{3}}\bigr)^{2} and \displaystyle \bigl(27^{\frac{1}{3}}\bigr)^{-2} first,
Then, the bases 125, 27 and 9 can be rewritten as
With the help of the power rules,
