Aus Online Mathematik Brückenkurs 1

The line should go through the points \displaystyle \left( 5 \right.,\left. 0 \right) and \displaystyle \left( 0 \right.,\left. -8 \right) which must therefore satisfy the equation of the line \displaystyle y=kx+m, i.e.

\displaystyle 0=k\centerdot 5+m

From the other equation, we get \displaystyle m=-8 and substituting this into the first equation gives

\displaystyle 0=5k-8\ \Leftrightarrow \ k={8}/{5}\;

The gradient of the line is \displaystyle {8}/{5}\;.