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Lösung 2.2:5b

Aus Online Mathematik Brückenkurs 1

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Because the straight line is to have a gradient of −3, its equation can be written as


y=−3x+m


where m is a constant. If the line is also to pass through the point xy=1−2 , the point must satisfy the equation of the line


−2=−31+m


which gives that m=1.

The answer is thus that the equation of the line is y=−3x+1.


Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.2:5b“