Aus Online Mathematik Brückenkurs 1

Move \displaystyle x to the left-hand side by subtracting \displaystyle 2x from both sides,

\displaystyle 5x+7-2x=2x-6-2x

which gives

\displaystyle 3x+7=-6

Subtract \displaystyle 7 from both sides,

\displaystyle 3x+7-7=-6-7

so that the term \displaystyle 3x alone remains on the left-hand side

\displaystyle 3x=-13

Then, divide both sides by \displaystyle 3

\displaystyle \frac{3x}{3}=-\frac{13}{3}

to get x:

\displaystyle x=-\frac{13}{3}