Lösung 1.1:2c

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We can divide up the whole expression into two separate parts

\displaystyle \bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,}

which we first calculate and then combine.

The first part of the expression equals

\displaystyle 3\cdot(-7) = -21

whilst the second expression becomes.

\displaystyle 4\cdot(6-5) = 4\cdot 1 = 4\,.

Combining, we obtain

\displaystyle \bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,.
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.1:2c“