Lösung 1.3:2a
Aus Online Mathematik Brückenkurs 1
We can write every factor in the expression as a power of 2,
| \displaystyle \begin{align}
2 &= 2^{1}\,, \\ 4 &= 2\cdot 2 = 2^{2}\,,\\ 8 &= 2\cdot 4 = 2\cdot 2\cdot 2 = 2^{3}\,, \end{align} |
which gives
| \displaystyle 2\cdot 4\cdot 8 = 2^{1}\cdot 2^{2}\cdot 2^{3} = 2^{1+2+3} = 2^{6}\,. |
