Lösung 4.4:4
Aus Online Mathematik Brückenkurs 1
The idea is first to find the general solution to the equation and then to see which angles lie between \displaystyle 0^{\circ} and \displaystyle 360^{\circ}\,.
If we start by considering the expression \displaystyle 2v+10^{\circ} as an unknown, then we have a usual basic trigonometric equation. One solution which we can see directly is
There is then a further solution which satisfies \displaystyle 0^{\circ}\le 2v + 10^{\circ}\le 360^{\circ}, where \displaystyle 2v+10^{\circ} lies in the third quadrant and makes the same angle with the negative y-axis as \displaystyle 100^{\circ} makes with the positive y-axis, i.e. \displaystyle 2v + 10^{\circ} makes an angle \displaystyle 110^{\circ} - 90^{\circ} = 20^{\circ} with the negative y-axis and consequently
Now it is easy to write down the general solution,
and if we make v the subject, we get
For different values of the integers n, we see that the corresponding solutions are:
| \displaystyle \cdots\cdots | \displaystyle \cdots\cdots | \displaystyle \cdots\cdots | ||
| \displaystyle n=-2: | \displaystyle v = 50^{\circ} - 2\cdot 180^{\circ} = -310^{\circ} | \displaystyle v = 120^{\circ } - 2\cdot 180^{\circ} = -240^{\circ} | ||
| \displaystyle n=-1: | \displaystyle v = 50^{\circ} - 1\cdot 180^{\circ} = -130^{\circ} | \displaystyle v = 120^{\circ} - 1\cdot 180^{\circ} = -60^{\circ} | ||
| \displaystyle n=0: | \displaystyle v = 50^{\circ} + 0\cdot 180^{\circ} = 50^{\circ} | \displaystyle v = 120^{\circ} + 0\cdot 180^{\circ} = 120^{\circ} | ||
| \displaystyle n=1: | \displaystyle v = 50^{\circ} + 1\cdot 180^{\circ} = 230^{\circ} | \displaystyle v = 120^{\circ} + 1\cdot 180^{\circ} = 300^{\circ} | ||
| \displaystyle n=2: | \displaystyle v = 50^{\circ} + 2\cdot 180^{\circ} = 410^{\circ} | \displaystyle v = 120^{\circ} + 2\cdot 180^{\circ} = 480^{\circ} | ||
| \displaystyle n=3: | \displaystyle v = 50^{\circ} + 3\cdot 180^{\circ} = 590^{\circ} | \displaystyle v = 120^{\circ} + 3\cdot 180^{\circ} = 660^{\circ} | ||
| \displaystyle \cdots\cdots | \displaystyle \cdots\cdots | \displaystyle \cdots\cdots |
From the table, we see that the solutions that are between \displaystyle 0^{\circ} and \displaystyle 360^{\circ} are
