Lösung 2.3:6c
Aus Online Mathematik Brückenkurs 1
If we complete the square of the expression, we have that
and because \displaystyle \bigl(x-\tfrac{5}{2}\bigr)^{2} is a quadratic, this term assumes a minimal value zero when \displaystyle x=5/2\,. This shows that the polynomial's smallest value is \displaystyle \tfrac{3}{4}.
