Lösung 2.1:1e

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If we use the rule for squaring \displaystyle (a-b)^2 = a^2-2ab+b^2 with \displaystyle a=x and \displaystyle b=7, we obtain directly that

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An alternative is to write the square as \displaystyle (x-7)\cdot (x-7) and then multiply the brackets in two steps

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In the line that has been marked with an asterisk, we have removed the bracket and at the same time changed signs on all terms inside the bracket.