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Lösung 2.2:5e

Aus Online Mathematik Brückenkurs 1

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The line should go through the points 50  and 0−8  which must therefore satisfy the equation of the line y=kx+m, i.e.


0=k5+m


From the other equation, we get m=−8 and substituting this into the first equation gives


0=5k−8  k=85


The gradient of the line is 85.


Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.2:5e“