Lösung 2.2:5b
Aus Online Mathematik Brückenkurs 1
Because the straight line is to have a gradient of \displaystyle -3, its equation can be written as
\displaystyle y=-3x+m
where
\displaystyle m
is a constant. If the line is also to pass through the point
\displaystyle \left( x \right.,\left. y \right)=\left( 1 \right.,\left. -2 \right), the point
must satisfy the equation of the line
\displaystyle -2=-3\centerdot 1+m
which gives that
\displaystyle m=1.
The answer is thus that the equation of the line is \displaystyle y=-3x+1.
