Lösung 1.3:2a

Aus Online Mathematik Brückenkurs 1

We can write every factor in the expression as a power of 2,

\displaystyle \begin{align} & 2=2^{1} \\ & \\ & 4=2\centerdot 2=2^{2} \\ & \\ & 8=2\centerdot 4=2\centerdot 2\centerdot 2=2^{3} \\ \end{align}

which gives

\displaystyle 2\centerdot 4\centerdot 8=2^{1}\centerdot 2^{2}\centerdot 2^{3}=2^{1+2+3}=2^{6}