Antwort 4.3:6
Aus Online Mathematik Brückenkurs 1
| a) | \displaystyle \sin{v}=-\displaystyle \frac{\sqrt{7}}{4}\quad och \displaystyle \quad\tan{v}=-\displaystyle \frac{\sqrt{7}}{3}\, |
| b) | \displaystyle \cos{v}=-\displaystyle \frac{\sqrt{91}}{10}\quad och \displaystyle \quad\tan{v}=-\displaystyle \frac{3}{\sqrt{91}}\, |
| c) | \displaystyle \sin{v}=-\displaystyle \frac{3}{\sqrt{10}}\quad och \displaystyle \quad\cos{v}=-\displaystyle \frac{1}{\sqrt{10}}\, |
