Lösung 4.4:8b
Aus Online Mathematik Brückenkurs 1
Suppose that \displaystyle \cos x\ne 0, so that we can divide both sides by \displaystyle \cos x to obtain
This equation has the solutions \displaystyle x = \pi/3+n\pi for all integers n.
If, on the other hand, \displaystyle \cos x=0, then \displaystyle \sin x = \pm 1 (draw a unit circle) and the equation cannot have such a solution.
Thus, the equation has the solutions
