Lösung 2.1:1b

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When the factor \displaystyle xy is multiplied by the expression inside the brackets, \displaystyle 1+x+x^2 , the distributive rule gives that all three terms \displaystyle 1, \displaystyle x and \displaystyle -x^2 are multiplied by \displaystyle xy,

\displaystyle \begin{align}

(1+x-x^2) &= 1\cdot xy + x\cdot xy -x^2\cdot xy\\[3pt] &= xy+x^2y-x^3y\,\textrm{.} \end{align}