Lösung 4.3:4e
Aus Online Mathematik Brückenkurs 1
The addition formula for sine gives us that
\displaystyle \sin \left( v+\frac{\pi }{4} \right)=\sin v\centerdot \cos \frac{\pi }{4}+\cos v\centerdot \sin \frac{\pi }{4}.
Because we know from exercise b that
\displaystyle \sin v=\sqrt{1-b^{2}}
we use that
\displaystyle \cos \frac{\pi }{4}=\sin \frac{\pi }{4}=\frac{1}{\sqrt{2}}
to obtain
\displaystyle \sin \left( v+\frac{\pi }{4} \right)=\sqrt{1-b^{2}}\centerdot \frac{1}{\sqrt{2}}+b\centerdot \frac{1}{\sqrt{2}}.