Lösung 4.2:1d

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The side marked \displaystyle x is the hypotenuse in the right-angled triangle and the side of length \displaystyle \text{16} is the adjacent to the angle of \displaystyle \text{2}0^{\circ }.


By writing the quotient for \displaystyle \text{cos20}^{\circ }, we obtain the relation


\displaystyle \text{cos20}^{\circ }=\frac{16}{x}


and this gives


\displaystyle x=\frac{16}{\text{cos20}^{\circ }}\quad \left( \approx 17.0 \right).