Antwort 4.3:6
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
K (hat „Answer 4.3:6“ nach „Antwort 4.3:6“ verschoben: Robot: moved page) |
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|a) | |a) | ||
| - | |width="100%" | <math>\sin{v}=-\displaystyle \frac{\sqrt{7}}{4}\quad</math> | + | |width="100%" | <math>\sin{v}=-\displaystyle \frac{\sqrt{7}}{4}\quad</math> und <math>\quad\tan{v}=-\displaystyle \frac{\sqrt{7}}{3}\,</math> |
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|b) | |b) | ||
| - | |width="100%" | <math>\cos{v}=-\displaystyle \frac{\sqrt{91}}{10}\quad</math> | + | |width="100%" | <math>\cos{v}=-\displaystyle \frac{\sqrt{91}}{10}\quad</math> und <math>\quad\tan{v}=-\displaystyle \frac{3}{\sqrt{91}}\,</math> |
|- | |- | ||
|c) | |c) | ||
| - | |width="100%" | <math>\sin{v}=-\displaystyle \frac{3}{\sqrt{10}}\quad</math> | + | |width="100%" | <math>\sin{v}=-\displaystyle \frac{3}{\sqrt{10}}\quad</math> und <math>\quad\cos{v}=-\displaystyle \frac{1}{\sqrt{10}}\,</math> |
|} | |} | ||
Aktuelle Version
| a) | \displaystyle \sin{v}=-\displaystyle \frac{\sqrt{7}}{4}\quad und \displaystyle \quad\tan{v}=-\displaystyle \frac{\sqrt{7}}{3}\, |
| b) | \displaystyle \cos{v}=-\displaystyle \frac{\sqrt{91}}{10}\quad und \displaystyle \quad\tan{v}=-\displaystyle \frac{3}{\sqrt{91}}\, |
| c) | \displaystyle \sin{v}=-\displaystyle \frac{3}{\sqrt{10}}\quad und \displaystyle \quad\cos{v}=-\displaystyle \frac{1}{\sqrt{10}}\, |
