Antwort 2.3:1
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="25%" | <math>(x-1)^2-1</math> |b) |width="25%" | <math>(x+1)^2-2</math> |c) |width="25%" | <math>-(x-1)^2+6</math> |d) |width="25%" | width="...) |
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| Zeile 7: | Zeile 7: | ||
|width="25%" | <math>-(x-1)^2+6</math> | |width="25%" | <math>-(x-1)^2+6</math> | ||
|d) | |d) | ||
| - | |width="25%" | | + | |width="25%" | <math>\bigl(x+\frac{5}{2}\bigr)^2-\frac{13}{4}</math> |
|} | |} | ||
Version vom 11:11, 1. Apr. 2008
| a) | \displaystyle (x-1)^2-1 | b) | \displaystyle (x+1)^2-2 | c) | \displaystyle -(x-1)^2+6 | d) | \displaystyle \bigl(x+\frac{5}{2}\bigr)^2-\frac{13}{4} |
