Antwort 4.3:6
Aus Online Mathematik Brückenkurs 1
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Version vom 17:48, 22. Okt. 2008
a) | \displaystyle \sin{v}=-\displaystyle \frac{\sqrt{7}}{4}\quad and \displaystyle \quad\tan{v}=-\displaystyle \frac{\sqrt{7}}{3}\, |
b) | \displaystyle \cos{v}=-\displaystyle \frac{\sqrt{91}}{10}\quad and \displaystyle \quad\tan{v}=-\displaystyle \frac{3}{\sqrt{91}}\, |
c) | \displaystyle \sin{v}=-\displaystyle \frac{3}{\sqrt{10}}\quad and \displaystyle \quad\cos{v}=-\displaystyle \frac{1}{\sqrt{10}}\, |