Lösung 4.2:2e
Aus Online Mathematik Brückenkurs 1
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Version vom 14:53, 22. Okt. 2008
This exercise is somewhat of a trick question, because we don't need any trigonometry to solve it.
Two angles are given in the triangle (the 60° angle and the right-angle) and thus we can use the fact that the sum of all the angles in a triangle is 180°,
| \displaystyle v + 60^{\circ} + 90^{\circ} = 180^{\circ}\,, |
which gives
| \displaystyle v = 180^{\circ} - 60^{\circ} - 90^{\circ} = 30^{\circ}\,\textrm{.} |
