Lösung 2.2:6b

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Version vom 13:59, 22. Okt. 2008

Because the point of intersection lies on both lines, it must satisfy the equations of both lines

\displaystyle y=-x+5\qquad\text{and}\qquad x=0\,,

where \displaystyle x=0 is the equation of the y-axis. Substituting the second equation, \displaystyle x=0, into the first equation gives \displaystyle y=-0+5=5. This means that the point of intersection is (0,5).


Image:2_2_6_b.gif