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Lösung 1.2:2a

Aus Online Mathematik Brückenkurs 1

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Version vom 13:26, 22. Okt. 2008

A common way to calculate the expression in the exercise is to multiply top and bottom of each fraction by the other fraction's denominator, so as to obtain a common denominator,

61+110=611010+11066=6010+660.

However, this gives a common denominator, 60, which is larger than it really needs to be.

If we instead divide up the fractions' denominators into their smallest possible integral factors,

123+125,

we see that both denominators contain the factor 2 and it is then unnecessary to include that factor when we multiply the top and bottom of each fraction.

61+110=6155+11033=530+330.

This gives the lowest common denominator (LCD), 30.

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.2:2a“