Lösung 4.2:2b
Aus Online Mathematik Brückenkurs 1
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The right-hand side in this equation can be simplified, so that we get | The right-hand side in this equation can be simplified, so that we get | ||
- | {{ | + | {{Abgesetzte Formel||<math>\sin v = \frac{7}{11}\,\textrm{.}</math>}} |
Version vom 08:51, 22. Okt. 2008
In this right-angled triangle, the opposite and the hypotenuse are given. This means that we can directly set up a relation for the sine of the angle v,
\displaystyle \sin v = \frac{70}{110}\,\textrm{.} |
The right-hand side in this equation can be simplified, so that we get
\displaystyle \sin v = \frac{7}{11}\,\textrm{.} |