Lösung 3.3:5f
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
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Since <math>\ln e=1</math>, the whole expression becomes | Since <math>\ln e=1</math>, the whole expression becomes | ||
| - | {{ | + | {{Abgesetzte Formel||<math>\bigl(e^{\ln e}\bigr)^2 = \bigl(e^{1}\bigr)^2 = e^{1\cdot 2} = e^2\,\textrm{.}</math>}} |
Version vom 08:44, 22. Okt. 2008
Since \displaystyle \ln e=1, the whole expression becomes
| \displaystyle \bigl(e^{\ln e}\bigr)^2 = \bigl(e^{1}\bigr)^2 = e^{1\cdot 2} = e^2\,\textrm{.} |
