Lösung 3.3:5a
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
			  			                                                      
		          
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| The notation ln is used for the logarithm with the natural base <math>e = 2\textrm{.}7182818\ldots\,,</math> and we therefore have that <math>\ln e = 1\,</math>, which together with the logarithm law, <math>b\lg a=\lg a^b</math>, gives that | The notation ln is used for the logarithm with the natural base <math>e = 2\textrm{.}7182818\ldots\,,</math> and we therefore have that <math>\ln e = 1\,</math>, which together with the logarithm law, <math>b\lg a=\lg a^b</math>, gives that | ||
| - | {{ | + | {{Abgesetzte Formel||<math>\ln e^3 + \ln e^2 = 3\cdot\ln e + 2\cdot \ln e = 3\cdot 1 + 2\cdot 1 = 5\,\textrm{.}</math>}} | 
Version vom 08:44, 22. Okt. 2008
The notation ln is used for the logarithm with the natural base \displaystyle e = 2\textrm{.}7182818\ldots\,, and we therefore have that \displaystyle \ln e = 1\,, which together with the logarithm law, \displaystyle b\lg a=\lg a^b, gives that
| \displaystyle \ln e^3 + \ln e^2 = 3\cdot\ln e + 2\cdot \ln e = 3\cdot 1 + 2\cdot 1 = 5\,\textrm{.} | 
 
		  