Lösung 3.3:2d

Aus Online Mathematik Brückenkurs 1

(Unterschied zwischen Versionen)
Wechseln zu: Navigation, Suche
K
K (Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel))
Zeile 1: Zeile 1:
If we compare the equality which defines <math>\mathop{\text{lg}} 1\,</math>,
If we compare the equality which defines <math>\mathop{\text{lg}} 1\,</math>,
-
{{Displayed math||<math>10^{\mathop{\text{lg}} 1} = 1\,,</math>}}
+
{{Abgesetzte Formel||<math>10^{\mathop{\text{lg}} 1} = 1\,,</math>}}
with
with
-
{{Displayed math||<math>10^{0} = 1</math>}}
+
{{Abgesetzte Formel||<math>10^{0} = 1</math>}}
we see that <math>\mathop{\text{lg}} 1 = 0\,</math>.
we see that <math>\mathop{\text{lg}} 1 = 0\,</math>.

Version vom 08:41, 22. Okt. 2008

If we compare the equality which defines \displaystyle \mathop{\text{lg}} 1\,,

\displaystyle 10^{\mathop{\text{lg}} 1} = 1\,,

with

\displaystyle 10^{0} = 1

we see that \displaystyle \mathop{\text{lg}} 1 = 0\,.

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_3.3:2d“