Lösung 3.1:2g

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Since <math>-125</math> can be written as <math>-125 = (-5)\cdot (-5)\cdot (-5) = (-5)^3</math>, the number <math>\sqrt[3]{-125}</math> is defined as
Since <math>-125</math> can be written as <math>-125 = (-5)\cdot (-5)\cdot (-5) = (-5)^3</math>, the number <math>\sqrt[3]{-125}</math> is defined as
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{{Displayed math||<math>\sqrt[3]{-125}=-5\,\textrm{.}</math>}}
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{{Abgesetzte Formel||<math>\sqrt[3]{-125}=-5\,\textrm{.}</math>}}
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Note: It is possible to write the calculation in the solution as
Note: It is possible to write the calculation in the solution as
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{{Displayed math||<math>\sqrt[3]{-125} = \sqrt[3]{(-5)^{3}} = (-5)^1 = -5\,,</math>}}
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{{Abgesetzte Formel||<math>\sqrt[3]{-125} = \sqrt[3]{(-5)^{3}} = (-5)^1 = -5\,,</math>}}
but one has to be careful when one calculates using negative numbers and fractional exponents. Sometimes, the expression is not defined and the usual power rules do not always hold. Look, for example, at the calculation
but one has to be careful when one calculates using negative numbers and fractional exponents. Sometimes, the expression is not defined and the usual power rules do not always hold. Look, for example, at the calculation
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{{Displayed math||<math>\begin{align}
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{{Abgesetzte Formel||<math>\begin{align}
-5 = (-125)^{1/3} = (-125)^{2/6} = \bigl((-125)^2\bigr)^{1/6} = 15625^{1/6}=5\,\textrm{.}
-5 = (-125)^{1/3} = (-125)^{2/6} = \bigl((-125)^2\bigr)^{1/6} = 15625^{1/6}=5\,\textrm{.}
\end{align}</math>}}
\end{align}</math>}}

Version vom 08:36, 22. Okt. 2008

Since \displaystyle -125 can be written as \displaystyle -125 = (-5)\cdot (-5)\cdot (-5) = (-5)^3, the number \displaystyle \sqrt[3]{-125} is defined as

\displaystyle \sqrt[3]{-125}=-5\,\textrm{.}


Note: As opposed to \displaystyle \sqrt{-125} (the square root of -125) which is not defined, \displaystyle \sqrt[3]{-125} is defined. In other words, there does not exist any number x which satisfies \displaystyle x^2 = -125, but there is a number x which satisfies \displaystyle x^3 = -125\,.


Note: It is possible to write the calculation in the solution as

\displaystyle \sqrt[3]{-125} = \sqrt[3]{(-5)^{3}} = (-5)^1 = -5\,,

but one has to be careful when one calculates using negative numbers and fractional exponents. Sometimes, the expression is not defined and the usual power rules do not always hold. Look, for example, at the calculation

\displaystyle \begin{align}

-5 = (-125)^{1/3} = (-125)^{2/6} = \bigl((-125)^2\bigr)^{1/6} = 15625^{1/6}=5\,\textrm{.} \end{align}

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_3.1:2g“