Lösung 2.1:3b
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
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If we take out the factor 5, we see that the expression can be factorized using the conjugate rule | If we take out the factor 5, we see that the expression can be factorized using the conjugate rule | ||
| - | {{ | + | {{Abgesetzte Formel||<math>\begin{align} |
5x^2-20&=5(x^4-4)\\ | 5x^2-20&=5(x^4-4)\\ | ||
&= 5(x^2-2^2)\\ | &= 5(x^2-2^2)\\ | ||
&= 5(x+2)(x-2)\,\textrm{.} | &= 5(x+2)(x-2)\,\textrm{.} | ||
\end{align}</math>}} | \end{align}</math>}} | ||
Version vom 08:22, 22. Okt. 2008
If we take out the factor 5, we see that the expression can be factorized using the conjugate rule
| \displaystyle \begin{align}
5x^2-20&=5(x^4-4)\\ &= 5(x^2-2^2)\\ &= 5(x+2)(x-2)\,\textrm{.} \end{align} |
