Lösung 2.1:3a
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
K |
K (Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)) |
||
Zeile 1: | Zeile 1: | ||
If we look at the expression, we see that it can be written as <math>x^2-6^2</math> and can therefore be factorized using the conjugate rule | If we look at the expression, we see that it can be written as <math>x^2-6^2</math> and can therefore be factorized using the conjugate rule | ||
- | {{ | + | {{Abgesetzte Formel||<math> x^2-36=x^2-6^2=(x+6)(x-6)\,\textrm{.}</math>}} |
Because the factors <math> x+6 </math> and <math> x-6 </math> are linear expressions, they cannot be factorized any further (as polynomial factors). | Because the factors <math> x+6 </math> and <math> x-6 </math> are linear expressions, they cannot be factorized any further (as polynomial factors). |
Version vom 08:22, 22. Okt. 2008
If we look at the expression, we see that it can be written as \displaystyle x^2-6^2 and can therefore be factorized using the conjugate rule
\displaystyle x^2-36=x^2-6^2=(x+6)(x-6)\,\textrm{.} |
Because the factors \displaystyle x+6 and \displaystyle x-6 are linear expressions, they cannot be factorized any further (as polynomial factors).