Lösung 1.2:1e

Aus Online Mathematik Brückenkurs 1

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The first step is to expand the fractions so that they have a common denominator,
The first step is to expand the fractions so that they have a common denominator,
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{{Displayed math||<math>\frac{8\cdot 4\cdot 3}{7\cdot 4\cdot 3}+\frac{3\cdot 7\cdot 3}{4\cdot 7\cdot 3}-\frac{4\cdot 7\cdot 4}{3\cdot 7\cdot 4}=\frac{96}{84}+\frac{63}{84}-\frac{112}{84}\,</math>.}}
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{{Abgesetzte Formel||<math>\frac{8\cdot 4\cdot 3}{7\cdot 4\cdot 3}+\frac{3\cdot 7\cdot 3}{4\cdot 7\cdot 3}-\frac{4\cdot 7\cdot 4}{3\cdot 7\cdot 4}=\frac{96}{84}+\frac{63}{84}-\frac{112}{84}\,</math>.}}
After that, the expression can be calculated by adding and subtracting the numerators
After that, the expression can be calculated by adding and subtracting the numerators
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{{Displayed math||<math>\frac{96}{84}+\frac{63}{84}-\frac{112}{84}=\frac{96+63-112}{84}=\frac{47}{84}\,</math>.}}
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{{Abgesetzte Formel||<math>\frac{96}{84}+\frac{63}{84}-\frac{112}{84}=\frac{96+63-112}{84}=\frac{47}{84}\,</math>.}}

Version vom 08:13, 22. Okt. 2008

The first step is to expand the fractions so that they have a common denominator,

\displaystyle \frac{8\cdot 4\cdot 3}{7\cdot 4\cdot 3}+\frac{3\cdot 7\cdot 3}{4\cdot 7\cdot 3}-\frac{4\cdot 7\cdot 4}{3\cdot 7\cdot 4}=\frac{96}{84}+\frac{63}{84}-\frac{112}{84}\,.

After that, the expression can be calculated by adding and subtracting the numerators

\displaystyle \frac{96}{84}+\frac{63}{84}-\frac{112}{84}=\frac{96+63-112}{84}=\frac{47}{84}\,.
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.2:1e“