Lösung 4.2:1f

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The side adjacent to the angle of 50° is marked ''x'' and the opposite is the side of length 19.
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[[Image:4_2_1_f.gif|center]]
[[Image:4_2_1_f.gif|center]]
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The side adjacent to the angle of
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If we write the tangent for the angle, this gives a relation which contains ''x'' as the only unknown,
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<math>\text{5}0^{\circ }</math>
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is marked
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<math>x</math>
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and the opposite is the side of length
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<math>\text{19}</math>.
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If we write the tangent for the angle, this gives a relation which contains
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<math>x</math>
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as the only unknown,
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<math>\tan 50^{\circ }=\frac{19}{x}</math>
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{{Displayed math||<math>\tan 50^{\circ} = \frac{19}{x}\,\textrm{.}</math>}}
This gives
This gives
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{{Displayed math||<math>x=\frac{19}{\tan 50^{\circ }}\quad ({}\approx 15\textrm{.}9)\,\textrm{.}</math>}}
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<math>x=\frac{19}{\tan 50^{\circ }}\quad \left( \approx 15.9 \right)</math>
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Version vom 14:22, 8. Okt. 2008

The side adjacent to the angle of 50° is marked x and the opposite is the side of length 19.

If we write the tangent for the angle, this gives a relation which contains x as the only unknown,

Vorlage:Displayed math

This gives

Vorlage:Displayed math

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_4.2:1f“