Lösung 3.3:5f

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Since
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Since <math>\ln e=1</math>, the whole expression becomes
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<math>\ln e=1</math>, the whole expression becomes
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{{Displayed math||<math>\bigl(e^{\ln e}\bigr)^2 = \bigl(e^{1}\bigr)^2 = e^{1\cdot 2} = e^2\,\textrm{.}</math>}}
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<math>\left( e^{\ln e} \right)^{2}=\left( e^{1} \right)^{2}=e^{1\centerdot 2}=e^{2}</math>
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Version vom 07:34, 2. Okt. 2008

Since \displaystyle \ln e=1, the whole expression becomes

Vorlage:Displayed math

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_3.3:5f“