Lösung 4.2:4d

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K (Lösning 4.2:4d moved to Solution 4.2:4d: Robot: moved page)
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If we use the unit circle and mark on the angle
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<center> [[Image:4_2_4d.gif]] </center>
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<math>\pi </math>, we see immediately that
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<math>\text{cos }\pi \text{ }=-\text{1 }</math>
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and
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<math>\text{sin }\pi \text{ }=0</math>.
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[[Image:4_2_4_d.gif|center]]
[[Image:4_2_4_d.gif|center]]
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Thus,
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<math>\tan \pi =\frac{\sin \pi }{\cos \pi }=\frac{0}{-1}=0</math>

Version vom 13:15, 28. Sep. 2008

If we use the unit circle and mark on the angle \displaystyle \pi , we see immediately that \displaystyle \text{cos }\pi \text{ }=-\text{1 } and \displaystyle \text{sin }\pi \text{ }=0.

Thus,


\displaystyle \tan \pi =\frac{\sin \pi }{\cos \pi }=\frac{0}{-1}=0

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_4.2:4d“